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70 lines
2.2 KiB
C++
70 lines
2.2 KiB
C++
// url_coder.cpp : 定义控制台应用程序的入口点。
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//
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#include "stdafx.h"
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#include "acl_cpp/stdlib/string.hpp"
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#include "acl_cpp/stdlib/url_coder.hpp"
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using namespace acl;
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int main(void)
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{
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url_coder coder1;
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coder1.set("name1", "value1");
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coder1.set("name2", 2);
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coder1.set("name3", true, "value%d", 3);
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coder1.set("name4", "中国人");
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printf("coder1 >> %s, name1: %s, name2: %s, name3: %s, name4: %s\r\n",
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coder1.to_string().c_str(),
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coder1["name1"], coder1["name2"], coder1["name3"], coder1["name4"]);
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coder1.del("name1");
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const char* ptr = coder1["name1"];
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printf("coder1 >> %s, name1: %s, name2: %s, name3: %s, name4: %s\r\n",
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coder1.to_string().c_str(), ptr ? ptr : "null",
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coder1["name2"], coder1["name3"], coder1["name4"]);
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//////////////////////////////////////////////////////////////////////////
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url_coder coder2;
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coder2 = coder1;
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coder2.set("name5", "&=value5=&");
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ptr = coder2["name1"];
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printf("--------------------------------------------------------\r\n");
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printf("coder2 >> %s, name1: %s, name2: %s, name3: %s, name4: %s, name5: %s\r\n",
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coder2.to_string().c_str(), ptr ? ptr : "null",
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coder2["name2"], coder2["name3"], coder2["name4"], coder2["name5"]);
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//////////////////////////////////////////////////////////////////////////
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url_coder coder3(coder2);
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coder3.set("name5", 5);
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coder3.set("name6", "=&外国人&=");
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ptr = coder3["name1"];
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printf("--------------------------------------------------------\r\n");
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printf("coder3 >> %s, name1: %s, name2: %s, name3: %s, name4: %s, name5: %s, name6: %s\r\n",
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coder3.to_string().c_str(), ptr ? ptr : "null",
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coder3["name2"], coder3["name3"], coder3["name4"],
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coder3["name5"], coder3["name6"]);
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//////////////////////////////////////////////////////////////////////////
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url_coder coder4;
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const char* s = "name1=value1&name2=2&name3=value3&name4=%D6%D0%B9%FA%C8%CB";
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coder4.decode(s);
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printf("--------------------------------------------------------\r\n");
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printf("coder4 >> %s, name1: %s, name2: %s, name3: %s, name4: %s\r\n",
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coder4.to_string().c_str(),
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coder4["name1"], coder4["name2"], coder4["name3"], coder4["name4"]);
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#ifdef WIN32
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printf("enter any key to exit ...\r\n");
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getchar();
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#endif
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return 0;
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}
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