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fix(Filter-blocks): disable highlight when no connected blocks
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815768c91d
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@ -191,13 +191,19 @@ export const useTableBlockProps = () => {
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},
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},
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onClickRow(record, setSelectedRow, selectedRow) {
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onClickRow(record, setSelectedRow, selectedRow) {
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const { targets, uid } = findFilterTargets(fieldSchema);
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const { targets, uid } = findFilterTargets(fieldSchema);
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const dataBlocks = getDataBlocks();
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// 如果是之前创建的区块是没有 x-filter-targets 属性的,所以这里需要判断一下避免报错
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// 如果是之前创建的区块是没有 x-filter-targets 属性的,所以这里需要判断一下避免报错
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if (!targets || !targets.length) return;
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if (!targets || !targets.some((target) => dataBlocks.some((dataBlock) => dataBlock.uid === target.uid))) {
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// 当用户已经点击过某一行,如果此时再把相连接的区块给删除的话,行的高亮状态就会一直保留。
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// 这里暂时没有什么比较好的方法,只是在用户再次点击的时候,把高亮状态给清除掉。
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setSelectedRow((prev) => (prev.length ? [] : prev));
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return;
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}
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const value = [record[ctx.rowKey]];
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const value = [record[ctx.rowKey]];
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getDataBlocks().forEach((block) => {
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dataBlocks.forEach((block) => {
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const target = targets.find((target) => target.uid === block.uid);
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const target = targets.find((target) => target.uid === block.uid);
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if (!target) return;
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if (!target) return;
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